8[2-(3+2x)]-2x=-10+2(1-9x)

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Solution for 8[2-(3+2x)]-2x=-10+2(1-9x) equation: 


Simplifying
8[2 + -1(3 + 2x)] + -2x = -10 + 2(1 + -9x)
8[2 + (3 * -1 + 2x * -1)] + -2x = -10 + 2(1 + -9x)
8[2 + (-3 + -2x)] + -2x = -10 + 2(1 + -9x)

Combine like terms: 2 + -3 = -1
8[-1 + -2x] + -2x = -10 + 2(1 + -9x)
[-1 * 8 + -2x * 8] + -2x = -10 + 2(1 + -9x)
[-8 + -16x] + -2x = -10 + 2(1 + -9x)

Combine like terms: -16x + -2x = -18x
-8 + -18x = -10 + 2(1 + -9x)
-8 + -18x = -10 + (1 * 2 + -9x * 2)
-8 + -18x = -10 + (2 + -18x)

Combine like terms: -10 + 2 = -8
-8 + -18x = -8 + -18x

Add '8' to each side of the equation.
-8 + 8 + -18x = -8 + 8 + -18x

Combine like terms: -8 + 8 = 0
0 + -18x = -8 + 8 + -18x
-18x = -8 + 8 + -18x

Combine like terms: -8 + 8 = 0
-18x = 0 + -18x
-18x = -18x

Add '18x' to each side of the equation.
-18x + 18x = -18x + 18x

Combine like terms: -18x + 18x = 0
0 = -18x + 18x

Combine like terms: -18x + 18x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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